This is my maths question paper .I have little bit doubts.in question no 8 part 3 my ans is 28.plc verify
also do the rectangle sum I can't do that
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Rectange problem》》》
Perimeter of Rect. = 2(l+b)
= 2(10+8)
=36 cm
Let x be added to 10 cm.
New perimeter = 2(10+x+8)
{Since perimeter is doubled}
2(10+x+8)= 36×2
18+x = 72/2
x= 36-18
x=18
Sides = 8cm & 10+8=18 cm
Area of rect.= l×b
=18×8
=144
8 (iii) 28 Ans.
Perimeter of Rect. = 2(l+b)
= 2(10+8)
=36 cm
Let x be added to 10 cm.
New perimeter = 2(10+x+8)
{Since perimeter is doubled}
2(10+x+8)= 36×2
18+x = 72/2
x= 36-18
x=18
Sides = 8cm & 10+8=18 cm
Area of rect.= l×b
=18×8
=144
8 (iii) 28 Ans.
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