Question

This is my question pls answer correctly ....!! NO SPAMS❌❌​

Answer 1

In ∆QOP and ∆APO

• ∠APO = ∠AQO [ 90° each ]

• AO = AO [ common ]

• ∠OAP = ∠QAO [Given ]

• ∆QOP ≈ ∆APO

• OP = OQ [ CPCT ]

With the help of pythogoras theorem ;

i.e.

(Hypotenuse)² = (Perpendicular)² + (base)²

AO² = AP² + OP²

(5)² = (4)² + OP²

25 - 16 = OP²

9 = OP²

$\boxed{\mathsf{PO = 9cm}}$

Therefore

The value of OQ = OP = 9cm

I HOPE IT HELPS.