Question

this is of three marks​

Answer 1

Step-by-step explanation:

Pashto picture Beagle I cannot see better

Answer 2

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$\frac{1}{x} + \frac{2}{2x - 3} = \frac{1}{x - 2} \\ \frac{2x - 3 + 2x}{2x { { }^{2} - 3x }^{} } = \frac{1}{x - 2} \\ \frac{4x - 3}{2x {}^{2} - 3 } = \frac{1}{x - 2} \\ 4x {}^{2} - 8x - 3x + 6 = 2x {}^{2} - 3 \\ 4x {}^{2} - 2x {}^{2} - 11x + 6 + 3 \\ 2x {}^{2} - 11x + 9 = 0 \\ 2x {}^{2} - 9x - 2x + 9 = 0 \\ x (2x - 9) - 1(2x - 9) = 0 \\ ( x- 1)(2x - 9) = 0$

Hence the value of x would be :

$x - 1 = 0$

$\huge{\mathcal{\blue{\underline{\implies{x=1}}}}}$

Or

$2x - 9 = 0 \\ 2x = 9$

$\huge{\mathcal{\blue{\implies{\underline{x=9/2}}}}}$