Question

this is the picture of question 19.​

Answer 1

Answer:

Let x = 2a, y = 3a & z = 4a

Angle AOD = 180°

According to the problem,

Angle AOB + Angle BOC + Angle COD = 180°

x + y + z = 180

2a + 3a + 4a = 180

9a = 180

a = 180/9

a = 20

Therefore,

• Angle AOB = x = 2a = 40°
• Angle BOC = x = 3a = 60°
• Angle COD = x = 4a = 80°