Math, asked by yamu11, 1 year ago

this one is tough..........

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Answered by sizaB
0
= x^2+y^2+z^2+2 (-xy+xz-yz)
=(x-y+z)^2
Since, (x+y+z)^2= X^2+y^2+z^2+1 ( xy+yz+zx)
Answered by Sanskriti141
1
Hii there!!

Plz refer to the attachment for the answer!!

Hope it helps....

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