Math, asked by goelmannan, 10 months ago

This question is for 24 points pls answer

if a=√3-√2/√3+√2 and b =√3+√2/√3-√2 then fund a^2+b^2 -5ab

Answers

Answered by ayush100040
0

Answer:

I hope this helps you

Step-by-step explanation:

please

follow

me

please

√3


goelmannan: What is this
Answered by siddhartharao77
2

Answer:

93

Step-by-step explanation:

(i)

Given: a = \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}} *\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}

= \frac{(\sqrt{3}-\sqrt{2})^2}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}

= \frac{(\sqrt{3}-\sqrt{2})^2}{(\sqrt{3})^2-(\sqrt{2})^2}

= (\sqrt{3}-\sqrt{2})^2

= 5 - 2\sqrt{6}

(ii)

Given: b = \frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}} *\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}

= \frac{(\sqrt{3}+\sqrt{2})^2}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}

= \frac{(\sqrt{3}+\sqrt{2})^2}{(\sqrt{3})^2-(\sqrt{2})^2}

= (\sqrt{3}+\sqrt{2})^2

= 5+2\sqrt{6}

Now,

a² + b² - 5ab

= (5 - 2√6)² + (5 + 2√6)² - 5(5 - 2√6)(5 + 2√6)

= 49 - 20√6 + 49 + 20√6 -  5[(5)² - (2√6)²]

= 98 - 5[25 - 24]

= 98 - 5

= 93

Hope it helps!


siddhartharao77: :)
Similar questions