Question

this question is from probability chapter. please solve. ​

Answer 1

Answer:

Hlw Let 3+2√3 is a rational number. A rational number can be written in the form of p/q. p,q are integers then (p-6q)/2q is a rational number. ... Therefore,3+2√3 is an irrational number.

Step-by-step explanation:

Answer 2

Answer:

P(A ∪ C)=7/13

Explanation:

Given that, P(B) = 3/2 P(A) and P(C) = 1/2 P(B)

As, A, B, and C are mutually exclusive events,

⇒ P(A)+P(B)+P(C)= 1

Now, substitute the given values in the formula,

⇒ P(A) + (3/2)P(A) + (½)P(B) = 1

⇒ P(A) + (3/2)P(A) +(½)(3/2)P(A) = 1

⇒ 13/4 P(A) = 1

⇒ P(A) = 4/13

⇒ P(C) = (½)(3/2)P(A)

⇒ P(C) = (½)(3/2)(4/13)

⇒ P(C) = 3/13

Given that, A, B, and C are mutually exclusive events,

⇒P(A ∩ B) = P(B ∩ C) = P(C ∩ A ) = 0

Hence, P(A ∪ C)= P(A) +P(C)-0

⇒P(A ∪ C)= (4/13)+(3/13)

∴P(A ∪ C)=7/13

I Hope you like it! If you are satisfied with my answer

Please mark me as Brainliest!!!