Math, asked by mehkshaikh12040, 11 months ago

This question is of linear equations. ..plz solve​

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Answers

Answered by aMaX728
2
Hey mate.
Here is your answer :--

Let the present age of Manish be x
and that of Savita be y

1st condition:-
x+y = 31. -----(1)

2nd condition
3 years ago Manish's age was x - 3
and that of Savita was y-3

so x-3 = 4(y-3)

x-3 = 4y - 12

x-4y = -12+3

x-4y = -9. ------(2)

Now,

Multiply equation 1 by 4

4x + 4y = 124. -----(3)

4x + 4y = 124
+ x - 4y = -9
-------------------

so, 5x = 115
x = 115/5
x = 23

substituting x =23 in equation (1)

so, 23 + y = 31

y = 31-23
y = 8

so the age of Manish is x = 23 yrs
and that of Savita is y = 8 yrs

Final answer :-

Present ages of Manish and Savita is 23 yrs and 8 yrs respectively

Hope this help you mate
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