Question

This Question is of Maths Plz Solve it as Fast as u can with correct answer if so I will give it asa brainliest answer and u will get 40 points tooo

Answer 1

Heya mate, Here is ur answer

Let the fixed charge be x.

And additional charges be y.

Given that fixed charges are for 3 days. So, x will be multiplied by 3 and the remaining days will be multiplied by y.

Sarita paid ₹27 for 7 days.

3×fixed charges +4×additional charges =27

3x+4y=27

Sunil paid ₹27 for 5 days

3x+2y=21

So, we get two equations

3x+4y=27
3x+2y=21

After eliminating we get

2y=6

y=6/2

y=3

Substituting y=3 in 3x+2y=21

3x+2×3=21

3x+6=21

3x=21-6

3x=15

x=15/3

x=5

$<b><u>So , Fixed charges=₹5 for 1 day or ₹15 for 3 days and additional charges =₹3 .</b></u>$

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@Laughterqueen

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Answer 2

Let the fixed be 'x'.

Let the charge for each extra day be 'y'.

(i) Read the question Carefully.

Saritha paid 27 and kept book for 7 days. fixed charge for 3 days, extra charge for remaining days.

⇒ x + 4y = 27    ----- (1)

(ii)

Sunil paid 21 for the book he kept for five days.

⇒ x + 2y = 21    ----- (2)

On solving (1) & (2), we get

⇒ x + 4y = 27

⇒ x + 2y = 21

   ----------------

          2y = 6

             y = 3.

Substitute y = 3 in (1), we get

⇒ x + 4y = 27

⇒ x + 12 = 27

⇒ x = 15

Therefore:

⇒ Fixed charge = 15 rupees.

⇒ Charge per day = 3 rupees.

Hope it helps!