Question

this question Mole concept

Answer fast please

what is the volume occupied by 11.2 g of the gas at NTP
If its Given that the vapour density of a gas is 11.2.?

Answer 1

HEYAA......

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$\implies$ we have given, Molecular mass of gas = 2 × Vapour density

$\implies$ A/c to Question..-->

$\implies$ = 2×11.2

$\implies$= 22.4

$\implies$No. of moles of gas = 11.2/22.4 = 0.5

Volume$\implies$ occupied by gas at NTP = moles × 22.4

$\implies$ = 0.5 × 22.4

$\implies$= 11.2 liters.

Answer 2

hi

here is your answer

Frnd ........ ☺

Molecular mass of the gas = 2×2×Vapour density of the gas

Molecular Mass = 2×11.2=22.4g/m2×11.2=22.4g/m

22.4 g of the gas = 1 mol of the gas

11.2 g of the gas = (1×11.2)22.4(1×11.2)22.4 = 0.5 mole of gas

1 mole of gas = 22.4 L of gas

∴∴ 0.5 mole of gas = (22.4×0.5)(22.4×0.5) = 11.2 L of gas




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