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By F.B.D of m mass block
T-umg = ma
T-0.5×1×10 = ma
T - 5 = a _____(1)
By F.B.D of 2m mass block
2mg - T = 2ma
20 - T = 2a _____(2)
From (1) & (2) we get
a=5 & T=10
S = v²-u²/2a
S = 100/10
S = 10 m
W.D by all Force = ∆K
W.D by friction + W.D by T = Kf - Ki
W.D(f) + 10.10 = 1/2.1.(10)² - 0
W.D(f) + 100 = 50
W.D(f) = -50 J. ans....
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Answer:
-50 joule (-ve sign shows workdone by friction is opposite to that of motion)
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