Question

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Answer 1

Step-by-step explanation:

In ∆PSR and ∆RQP,

PQ=SR (Given)

QPR=SRP (Alternate interior angles)

PR=PR (Common)

∆PSR≈∆RQP

Yes,PS=QR (c.p.c.t)

Answer 2

In ΔPSR and ΔRQP,

• PQ = SR ( Given )
• PR = PR ( Common )
• PS = QR ( Parallel Sides adjacent to equal opposite sides are equal, i.e, it is forming a parallelogram)

Therefore,

ΔPSR ≈ ΔRQP (By S-S-S congruency)

Also, PS = QR (Equal opposite Sides of a parallelogram)