Math, asked by sonamsharan7602, 1 year ago

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Answered by ShanAgrawal
1
Here's ur ans friend nd plzz mrk brainliest.....
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Answered by siddhartharao77
2
Given LHS = 1/cosec A - cot A - 1/sinA

On rationalizing, we get

 \frac{1}{cosecA - cotA} *  \frac{cosecA + cotA}{cosecA+cotA} -  \frac{1}{sinA}

 \frac{cosecA + cotA}{cosec^2A - cot^2A} -  cosecA

NOTE: We know that cosec^2A - cot^2A = 1 and 1/sinA = cosecA

 \frac{cosecA + cotA}{1} - cosecA

cosecA + cotA - cosecA

cotA.  ---------------------------------------------- (1)



Given RHS = 1/sinA - 1/cosecA + cotA

On rationalizing, we get

 \frac{1}{sinA} -  \frac{1}{cosecA + cotA} *  \frac{cosecA - cotA}{cosecA - cotA}

 \frac{1}{sinA} -  \frac{cosecA + cotA}{cosec^2A - cot^2A}

cosecA -  \frac{cosecA + cotA}{1}

cosecA - cosecA + cotA

cot A   ----------------------- (2).



From (1) & (2), LHS = RHS.


Hope this helps!
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