Thr product of two numbers is 5476. if the hcf of these no is 37. the greater no is
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Let the numbers be 37a and 37b. Then , 37a x 37b =4107 => ab = 3.
Now co-primes with product 3 are (1,3)
So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).
Therefore, Greater number = 111.
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Concept-
HCF is the highest common factor. 37 is a common factor for 2 numbers. Take LCM as x and find the product of 2 numbers and get the value of x and then find the largest number.
Given-
The product of 2 numbers is given as 5476
The HCF of these numbers is given as 37.
Find-
Find the greatest number.
Solution-
Let us assume that LCM = x and HCF = 37.
HCF × LCM = Product of 2 numbers.
∴37x = 5476
∴x = 5476 / 37
∴ x = 148
So , 2 numbers are 37 and 148
Therefore , Greatest number = 148
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