Question

Three 2 Ω resistors A, B, C are connected as shown in fig. Each of them dissipates energy and can withstand a maximum power of 18 W without melting. Find the Maximum current that can flow through the three resistors?

Answer 1

Answer:

By using Ohm's law,

V=IR,

where,

V= voltage across a resistor

I = current through the resistor

R = value of resistance.

The power dissipated by the resistor is given by P=

R

V

2

=I

2

R

thus I

2

=

R

P

Each resistance dissipates energy = 18 Watts

The maximum current through B or C or A is given by I

2

=

2 ohms

18 Watts

So I=3 Amperes maximum.

Hope this answer helps.