three angles of quadrilateral are x°(2x+13) (3x+10) (x-6) .then what is the value of x.
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Sum of angles in a quadrilateral is 180°
let
ABCD is a quadrilateral
A + B + C + D = 180°
x(2x+13) + (3x+10) + (x-6) + D = 180°
(2x+13x) + (3x+10) + (x-6) = 180°
{2x+13x+3x+x} + { 10 - 6 } = 180°
{ 19x } + { 4} = 180°
Remove brackets
19x + 4 = 180°
19x = 180 - 4
19x = 176
x = 176 / 19
X = 9.26 ~ 9.27
let
ABCD is a quadrilateral
A + B + C + D = 180°
x(2x+13) + (3x+10) + (x-6) + D = 180°
(2x+13x) + (3x+10) + (x-6) = 180°
{2x+13x+3x+x} + { 10 - 6 } = 180°
{ 19x } + { 4} = 180°
Remove brackets
19x + 4 = 180°
19x = 180 - 4
19x = 176
x = 176 / 19
X = 9.26 ~ 9.27
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