write an expression for equivalent magnetic moment of plane current loop of area A, having N turns and carrying a current i.use this expression to find the magnetic dipole moment of revolving electron.
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m=niA
For a revolving electron,
I=q/t = e/T = e/2pier/v = ev/2pie r
So, m=N(ev/2pie r)*pie r^2= N(evr/2)
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Answered by
9
For equivalent magnetic moment of plane current loop of area A, having N-turns and carrying a current is, m= ANi
For a revolving electron the equation is,
m= N(evr/2)
Image is provided below for more conceptual clearance.
Attachments:
![](https://hi-static.z-dn.net/files/da0/6e1a8d25571b807809601de169d77bb9.jpg)
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