Three athletes Anuj,Amit and Anshul with tuning speed of 20m/s,40m/s and 60m/s respectively runs in the same direction on a circular track 1km long.If they all start together .Then how much time will they meet again?
Krissss:
Can anyone tell me?
Answers
Answered by
0
Answer:
50 seconds.
Step-by-step explanation:
We first need to get the time each takes to complete one lap.
Time = Distance / Speed.
We convert the distance to meters.
1 km = 1000 meters.
Anuj = 1000/20 = 50 seconds
Ankit = 1000/40 = 25 seconds
Anshul = 1000/60 = 50/3 seconds
We need to get the LCM of the three numbers.
Given that we have a fraction among the numbers we need to use a formula to get the LCM.
Given two factions a/b and c/d their lcm will be :
(lcm of a, c) / (HCF of b, d )
We apply this as follows :
50/1, 25/1, 50/3
LCM = (LCM 25,50,50) / (HCF 1,1, 3)
The LCM of 25, 50 and 50 = 50
The HCF of 1, 1, 3 = 1
The LCM of the three numbers is thus:
50/1 = 50
It therefore takes the three athlete 50 seconds to meet again.
Similar questions