Three bags contain total 24 coconuts. First and second bag contains total 11 coconuts, second
and third bag contains total 18 coconuts. How many coconuts are there in first and third bag
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Answer:
19 coconuts
Step-by-step explanation:
Total coconuts = 24
⇒ 1 Bag A + 1 Bag B + 1 Bag C = 24 coconuts
⇒ 2 Bag A + 2 Bag B + 2 Bag C = 48 coconuts
Given:
Bag A + Bage B = 11 coconuts
Bag B + Bag C = 18 coconuts
Add them together:
⇒ 1 Bag A + 2 Bag B + 1 Bag C = 11 + 18 coconuts
⇒ 1 Bag A + 2 Bag B + 1 Bag C = 29 coconuts
Now we know:
2 Bag A + 2 Bag B + 2 Bag C = 48 coconuts --------- [ 1 ]
1 Bag A + 2 Bag B + 1 Bag C = 29 coconuts --------- [ 2 ]
[ 1 ] - [ 2 ]:
1 Bag A + 1 Bag C = 48 - 29 coconuts
1 Bag A + 1 Bag C = 19 coconuts
Answer: 19 coconuts
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