Three beakers namely a, b and
c. each contain 100 ml of milk 1 m water solution. the ratio of milk to water in the beakers a, b and c is 1 : 3, 1 : 4 and 2 : 3 respectively. 40 ml of solution is transferred from beaker a to beaker c and than 28 ml of solution is transferred from beaker c to beaker
b. find the final ratio of milk in the beakers a, b and
c.
Answers
Each beaker has 100 ml of milk and water solution
BREAKER A:
Breaker A = Milk : Water = 1 : 3
Milk = 1/4 x 100 = 25 ml
Water = 3/4 x 100 = 75 ml
BREAKER B:
Breaker B = Milk : Water = 1 : 4
Milk = 1/5 x 100 = 20 ml
Water = 4/5 x 100 = 80 ml
BREAKER C:
Breaker C = Milk : Water = 2 : 3
Milk = 2/5 x 100 = 40 ml
Water = 3/5 x 100 = 60 ml
------------------------------------------------------------------------------------------
40ML OF SOLUTION IS TRANSFER FROM BEAKER A TO C:
Milk Transferred = 1/4 x 40 = 10ml
Water Transferred = 3/4 x 40 = 30 ml
Breaker A:
Milk = 25 - 10 = 15 ml
Water = 75 - 30 = 45 ml
Breaker C:
Milk = 40 + 10 = 50 ml
Water = 60 + 30 = 90 ml
New Ratio of Beaker C:
New Ratio = 50 : 90
(Simplify by dividing by 10)
Ratio = 5 : 9
------------------------------------------------------------------------------------------
28 ML OF SOLUTION IS TRANSFERRED FROM BEAKER C to B
Milk transferred = 5/14 x 28 = 10 ml
Water transferred = 9/14 x 28 = 18 ml
Beaker C:
Milk = 50 - 10 = 40 ml
Water = 90 - 18 = 72 ml
Beaker B:
Milk = 20 + 10 = 30 ml
Water = 80 + 18 = 98 ml
------------------------------------------------------------------------------------------
RATIO OF MILK:
Milk in Beaker A = 15 ml
Milk in Beaker B = 30 ml
Milk in Beaker C = 40 ml
Ratio of Milk in Beaker A : B : C = 15 : 30 : 40
(Simplify by diving by 5)
Ratio = 3 : 6 : 8
------------------------------------------------------------------------------------------
Answer: Ratio of Milk = 3 : 6 : 8
------------------------------------------------------------------------------------------