Math, asked by radhamishra616, 7 months ago

three bells commence tolling simultaneously if tearing at an interval of 40 second 48 second and 50 second . if there and together at 7 a.m. at what time will they rang together again

Answers

Answered by vasanthaallangi40
1

To find the time at which they all ring together again, first of all, we have find their LCM ( Least Common Multiple )

And, add it to the time at which they rang first .

LCM of 40, 48, 50 is 120 .

So, after 120 seconds all the bells will ring simultaneously .

120 seconds ÷ 60 seconds = 2 hours .

7 a.m + 2 hrs = 9 a.m

Solution : 9 a.m

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Answered by THEGOODBOY90
6

Answer:

ur answer is 9.am

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