three bells commence tolling simultaneously if tearing at an interval of 40 second 48 second and 50 second . if there and together at 7 a.m. at what time will they rang together again
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To find the time at which they all ring together again, first of all, we have find their LCM ( Least Common Multiple )
And, add it to the time at which they rang first .
LCM of 40, 48, 50 is 120 .
So, after 120 seconds all the bells will ring simultaneously .
120 seconds ÷ 60 seconds = 2 hours .
7 a.m + 2 hrs = 9 a.m
Solution : 9 a.m
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Answer:
ur answer is 9.am
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