three bells ring at intervals of 20 minutes 30 minutes and 45 minutes respectively if all three bells ring together at 3 a.m. then at what time will all the three bells ring together again?
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Answered by
3
Answer:
To find the minimum time,we have to find the LCM of 20,25,30
20=2*2*5
25=5*5
30=3*2*5
LCM =2*2*3*5*5
=300 minutes
=5 hours
therefore,at 4 p.m, they will meet again
Step-by-step explanation:
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Answered by
2
Step-by-step explanation:
From the given information we concluded that we have to find the LCM of the 20,30,45
LCM of the 20,30,45 = 180
Hence they will meet after 3 hours at 6 a.m.
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