Math, asked by sruthij1704, 8 months ago

Three bells ring similtaneously at 11:00 a.m. They ring at regular intervals of 20 mins, 30 mins, & 40 mins repectively. What is the time when all the three bells will ring to gether again​

Answers

Answered by mohit921
2

Answer:

Hence, the bells will toll together age in after 2 hours i.e. at 1 pm

(A+B)′s1days work

=12.....(i)

(B+C)′s1 day′s work

=115....(ii)

∴Difference between AandC′s1 days work

=112−115=5−460=160

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Answered by bommidiprabhath09876
3

Step-by-step explanation:

1 st bell rings every 20 min

2 nd bell rings every 30 min

3 rd bel rings every 40 min

lcm of 20, 30 ,40 is 120

all three bells ring at a time after 120 min from 11 a.m that is 1 : 00 p.m

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