Three blocks A, B and C are suspended as shown
in figure. Mass of each of blocks A and B is m. If
system is in equilibrium, and mass of C is M then
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Answered by
5
Answer:
Explanation:
=> Tension in the thread when system is in equilibrium:
T=mg ...(1)
=> As per the figure, from the equilibrium of the nodal point P
2Tcosθ=Mg
=> Place the value of T from equation (1), we get
2mgcosθ = Mg
2mcosθ = M
cosθ = M / 2m
cosθ < 1 (for θ cannot be 90°)
M / 2m < 1
∴ M < 2m
Answered by
3
Answer:Tension in the thread when system is in equilibrium:
T=mg ...(1)
=> As per the figure, from the equilibrium of the nodal point P
2Tcosθ=Mg
=> Place the value of T from equation (1), we get
2mgcosθ = Mg
2mcosθ = M
cosθ = M / 2m
cosθ < 1 (for θ cannot be 90°)
M / 2m < 1
∴ M < 2m.
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