Three blocks A, B and C of masses 2 kg, 3 kg and 3 kg respectively are arranged on smooth horizontal surface as shown in figure. If a force of 200 N acts on block A, then choose the correct option(s). [Assume all surfaces are smooth]
Answers
Answered by
1
Answer:
Solution
verified
Verified by Toppr
Correct option is A)
Total mass of three blocks:M=5+2+1=8kg
Acceleration of the blocks: a=
M
F
=
8
16
=2
Let N
AB
and N
BC
be the force exerted by block A on B and by block B on C respectively.
F−N
BA
=m
A
a where N
AB
=N
BA
∴16−N
BA
=5×2=10
⇒N
BA
=6=N
AB
N
AB
−N
CB
=m
B
×a=2×2=4
∴N
CB
=N
BC
=6−4=2
∴
N
BC
N
AB
=
2
6
=
1
3
Similar questions