Question

Three blocks A, B,C are such as M1=2 kg , M2=3 kg , M3=6 kg They are connected as shown in the below figure. The coefficient of friction between the block M2 and table is 0.2 Find out the following (a) Draw all the forces acting on the system (b) The acceleration of the system (c) Frictional force between the block M2 and table (d) Tension in the cord on the left and tension in the cord on the right Given g=10 m/sec2 The pulley are light and friction less ​

Answer 1

Answer:

Let a be the acceleration of the system.

T

1

=M

1

a .....(1)

T

2

−T

1

=M

2

a ....(2)

F−T

2

=M

3

a ......(3)

Adding (1), (2) and (3) we get

(M

1

+M

2

+M

3

)a=F

or (10+20+30)a=60⇒a=1m/s

2

Now , T

2

=(M

1

+M

2

)a=(10+20)(1)=30N