Three blocks of masses 6kg. 4kg and 2kg are pulled on a rough surface by applying a constant force
20 N. The values fo coefficient of friction between blocks and surface are shown in figure. (u = 0.2)
(
20 N
6 kg
4 kg
2 kg
13. In the arrangement shown tension in the string connecting 4 kg and 6 kg masses is
(
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Answer:
8 Newton
Explanation:
Maximum friction force that can act f
max
=μ(N
1
+N
2
+N
3
)
⟹f
max
=μ(m
1
+m
2
+m
3
)g=0.2(6+4+2)×10=24N
Since F=20N<f
max
, hence body will not move.
For equilibrium of m
1
-
T
1
=F−f
1
=F−μm
1
g=20−0.2×2×10=16N
For equilibrium of m
2
-
T
2
=T
1
−f
2
=T
1
−μm
2
g=16−0.2×4×10=8N
Hence tension in the string between 4kg and 6kg body is 8N.
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