Three bodies A (1kg), B (2kg) and C(3kg) are connected
by light inextensible strings and the system is pulled
with a force F. If the tension in the string connecting B
and C is 4.5N, the force F is
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consider all A B C all in one system
so a =F /m= F/6
draw fbd of a and b as one system
so T on right hand
so F = ma
T = ma
4.5 = 3F/6
F = 9N
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