Question

Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand, what is the minimum number of packets of each brand, he should buy?

Answer 1

LCM of 12 = 2^2 * 3

LCM of 15 = 3 * 5

LCM of 21 = 3 * 7

LCM of 12,15,21 = 420


Brand  A = 420/12 = 35
Brand B = 420/15 = 28
Brand C = 420/21 = 20


Hope this helps!

Answer 2

Answer:

brand A=35

brandB=28

brandC=20

Step-by-step explanation:

LCM of 12 = 2^2 * 3

LCM of 15 = 3 * 5

LCM of 21 = 3 * 7

LCM of 12,15,21 = 420  

Brand  A = 420/12 = 35

Brand B = 420/15 = 28

Brand C = 420/21 = 20