Question

Three brands A, B and C of biscuits are available in packets of 12,
15 and 21 biscuits respectively. If a shopkeepeer wants to buy an
equal number of biscuits, of each brand, what is the minimum
number of packets of each brand, he should buy?

Answer 1

$\textbf{Answer:}$


We have to find the lcm of 12,15 and 21,


$\bf{lcm \: of \: 12 = 2 \times 2 \times 3 } \\ \\\bf{lcm \: of \: 15 = 3 \times 5} \\ \\ \bf{lcm \: of \: 21 = 3 \times 7}$
The LCM of 12, 15 and 21 is= 2 x 2 x 3 x 5 x 7

=420

$\bf{minimum \: packets \: of \: a = } \frac{420}{12} = 35 \\ \\ \bf{minimum \: packets \: of \: b = \frac{420}{15}} = 28 \\ \\ \bf{minimum \: packets \: of \: c = \frac{420}{21} = 20 }$

$\textbf{Hope it helps you!}$

Answer 2

Lcm of. 12 =2*2*3
Lcm of 15= 3*5
Lcm of 21=3*7

Lcm of 12 and 15 and 21 is 2*2*3*7

a=420/12=35
b=420/15=28
c=420/21=20

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