Three brothers have some money. The oldest has 3/5 of the total, and the youngest has 1/10 of the total. If the oldest brother has $108, how much do each of the other brothers have?
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Answered by
5
younger brother will have 18dollars and the middle brother will have 54dollars
bhavana53:
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Answered by
2
Let the total be x
therefore
3/5x=108
solve it to get
x=180
Amount received by the youngest son=
1/10 of 180= 18
Total amount =180
Therefore,
180-(108+18)=54= Amount received by the second son
Hope I could help you.....:)
therefore
3/5x=108
solve it to get
x=180
Amount received by the youngest son=
1/10 of 180= 18
Total amount =180
Therefore,
180-(108+18)=54= Amount received by the second son
Hope I could help you.....:)
Thanks know I know HOW to do it the correct way!
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