Question

Three capacitors are connected as shown in the figure . The potential at point O is equal to

Answer 1

Answer:

To solve this question we first need to calculate the equivalent impedance of each capacitor.

Formula for calculating the impedance is equal to (1/ jw C) where C is capacitance of capacitor.

Now we need to apply Kirchhoff’s' Current law to find the potential at point O.

This law states that the sum of currents leaving a node is equal to the sum of currents entering the node.

Answer 2

Given:

The three capacitors with capacitance 1, 7 and 2

To find:

The potential at point O

Solution:

The formula of charge is

Q=C.V

As we know that sum of charges is equal to zero

Applying the property here.

Q+Q'+Q"=0

CV+C'V'+C"V"=0

Putting the values

1.(V-10)+2(V-4)+7(V)=0

V-10+2V-8+7V=0

10V=18

V=1.8

So, the option D is correct.