Question

Three capacitors of 2uF, 3 uF and 6uF are joined in series and the combination is
charged by means of a 30-volt battery. The potential difference between the plates of the
6 uF capacitor is
(a) 10 volts
(b) 5 volts
(c) 6 volts
(d) 8 volts​

Answer 1

Ceq. =1uF

V=30V

so, q=CV=30uC

In ,series charge remain same on every capacitor so for 6uF capacitor:

q=30uC

C=6uF

Hence, V=q/C

= 30/6

=5Volts

Ans:5 Volts

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Answer 2

Answer:

B

Explanation:

pd=v/c

=30/6

=5 volt