Question

Three capacitors of capacitances 2pF,3pF and 4pF are connected in parallel. What is the total capacitance of the combination?

Answer 1

in parallel the total capacitance is 2+3+4 = 9 pF

Answer 2

Answer:

Capacitance of three capacitors are given by;

C(1) = 2 pF

C(2) = 3 pF

C(3) = 4 pF

Since the three capacitors are arranged in parallel connection, so their capacitance will be;

C(total) = C(1) + C(2) + C(3)

Substituting the values;

C(total) = [2+ 3+ 4] pF = 9 pF

The total capacitance of the combination is 9 pF