Question

Three capacitors of capacities 8muF, 8muF and 4muF are connected in series and a potential difference of 120 volts in maintained across the combination. Calculate the charge on the capacitor of capacity 4muF.

Answer 1

Given: C 1 = 8 μF, C 2 = 8 μF, C 3 = 4 μF, V = 120 volt

To find: Charge on the capacitor C 3

`1/C_s=1/C_1+1/C_2+1/C_3`

`C=Q/V`

`1/C_s=1/C_1+1/C_2+1/C_3`

`=1/8+1/8+1/4`

`C_s=2muF=2xx10^-6F

In series combination,

Q1 = Q2 = Q3

Using formula (ii),

`Q = C_sV`

`Q=2xx10^-6xx120=240xx10^-6C`

Answer 2

Answer:

240muC

Explanation:

Ceq=2muF

q=Ceq×Vnet=2×120=240 muC

in series combination charge is same so charge on 4 muF capacitor is also 240 muC

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