Two capacitors of capacitances 3 muF and 6 muF, are charged to potentials 2V and 5V respectively. These two charged capacitors are connected in series. Find the potential across each of the two capacitors now.
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Take this answer, given below:
C1 =3 and C2 = 6
Equivalent C = 3×6/(6+3) = 2
Total potential V = 2+4=7V
Charge when connected in series Q = C×V = 2×7=14
V1 = Q/C1 = 14/3 = 4.66V
V2= Q/C2 =14/6 =2.33V.
Hope this is ur required answer.
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