Question

Three charge q,q and q are placed vertical of a right angle isosceles triangle find net eleectric potential

Answer 1

Answer:

Potential Energy Of System Of two Charge -

U=\frac{kQ_{1}Q_{2}}{r} \left ( S.I \right )

U= \frac{Q_{1}Q_{2}}{r} \left ( C.G.S \right )

- wherein

K=\frac{1}{4\pi \epsilon _{0}}

Potential energy of the configuration is

U = k\cdot\frac{Qq}{a} + k\frac{q^2}{a} + k\frac{qQ}{a\sqrt2} = 0 \Rightarrow Q = \frac{-\sqrt2 q}{\sqrt2 + 1}