Question

Three charged particles having charges q, -2q ,q are placed in a line at points -a,o. 0,0. a,0. The electric potential at points p(r,0). Is

Answer 1

Answer ⇒ 2kqa²/r(r² - a²)

Explanation ⇒ At a point P(r,0), Potential will be due to three charges namely q, -2q , and q.

Now,

Potential at Point P due to -2q = k(-2q)/r = -2kq/r

Potential at point p Due to q = kq/(r-a) + kq/(r + a)

= kq[r + a + r - a]/(r² - a²)

= 2kqr/(r² - a²)

Net Potential =  Potential at Point P due to -2q +  Potential at Point P due to q

∴ Net Potential = -2kq/r + 2kqr/(r² - a²)

= 2kq[-1/r + r/(r² - a²)]

= 2kq[-r² + a² + r²]/r(r² - a²)

= 2kqa²/r(r² - a²)

Hence, the net potential at point P is 2kqa²/r(r² - a²).

Hope it helps.

Answer 2

Answer:

Explanation:

Down and in photo