Question

.Three charges are arranged on vertices of an
equilateral triangle ABC of side a as shown. The magnitude of
clectric field of point Pon the angular bisector of A and at a
gayx
distance d' from Ald» a) is
where x and y are co-
yeond3
prime. Value of (xy) is equal to
​

Answer 1

The force at A due to charge +Q at C is outward from C and the force at A due to charge -Q at B.

Explanation:

• So, the resultant is parallel to BC.
• Thus there will no force in a direction normal to BC.
• Force due to both charge at B and C are equal in magnitude.
• Let, q and −q are placed at A and C  
• where 2q on B
• So, ≤n>hofA = d
• So, the dipo ≤ moment = (q×d) = P
• So, resultant dipole moment .
• P =[(qd)2+(qd)2+2qdqdcos60]12
•   =[d2q2+d2q2+2d2q2×12]12
•   =[3q2d2]12=3–√qd.

To Learn More...

1.if ABCD is a parallelogram and the angular bisectors of angle A and angle B meet at O , prove that angle AOB is a right angle

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