Question

Three children share some sweets in the ratio of their ages. The children are 4, 7 and 9

years old. The oldest child gets 63 sweets.

A) How many sweets do the other children get?

B) How many sweets do they share? ​

Answer 1

Answer:

So the ratio of ages is 4:7:9

Now 4+7+9=20

A) Total sweets=

$9x = 63 \\ \\ \therefore \: x = \frac{ \cancel {63} \: \: ^{7} }{ \cancel{9}} \\ \\ = 7 \times 20 = 140 \: sweets$

B)

$\frac{4}{ \cancel{20}} \times \cancel{140} \: \: ^{7} \\ \\ = 7 \times 4 = 28$

Age 4 gets 28 sweets.

$\frac{7}{ \cancel{20}} \times \cancel{140} \: \: ^{7} \\ \\ = 7 \times 7 = 49 \: sweets$

Age 7 gets 49 sweets.

Hope it helps you from my side