Math, asked by pprabh82001, 1 year ago

three circles are placed on a plane in such a way that each circle just touches the other two ,each having radius of 10 cm .find the area enclosed

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Answered by santy2

First construct a triangle joining centers of three circles as this will results into an equilateral triangle with sides20(10+10)
Then find the area of the triangle.
Then you should construct three sectors from each center with each sector touching two sectors on both sides.
Then calculate the area of the sectors.
Subtract the area of the sector from that of the triangle to get accurate answer.
=16.1

kvnmurty: each sector of the triangle encloses 60 deg. So a total of 180 deg. at the center of the arcs. So half the area of a circle... pi 10^2 /2...... area of triangle joining centers= sqrt(3)/4 * 20^2......so ans : 100 [ sqrt(3) - pi/2 ]

Answered by Mrcool566

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