Question

three circles each of radius 1 touch one another externally and they lie between two Parallel Lines the minimum possible distance between the lines is​

Answer 1

Answer:

Answer is $2+\sqrt{5}$ cm.

Step-by-step explanation:

Dear Student,

This is numerical problem,

So, see the attachment for explanation.

Answer 2

Answer:

minimum possible distance between the lines is 2 + √3

Step-by-step explanation:

According to given statement, the diagram is shown in figure-1

In triangle Δ AOB

By Pythagoras theorem,

AO² + OB² = AB²

AO² + 1² = 2²

AO² + 1  = 4

     AO²  = 4 -1

      AO²  = 3

       AO  = √3

minimum possible distance between the lines is​ calculated as,

AF + AO + BG

⇒1 + √3 + 1

⇒2 + √3

Hence, minimum possible distance between the lines is 2 + √3