three circles each of radius 3.5 cm are drawn in such a way that each touches the other two.find the area enclosed between these circles.
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Area which is enclosed in between these three circles
= area of equilateral triangle - area of sectors
= Ar(ABC) - 3(area of sector)
= √3/4 r² - 3(∅/360)(πr²)
= (√3/4) - 3(60/360)(22/7)(3.5)²
= (√3/4) - (1/2)(22)(7/4)
= (√3/4) - (77/4)
= (√3 -77)/4 cm²
Hope This Helps :)
= area of equilateral triangle - area of sectors
= Ar(ABC) - 3(area of sector)
= √3/4 r² - 3(∅/360)(πr²)
= (√3/4) - 3(60/360)(22/7)(3.5)²
= (√3/4) - (1/2)(22)(7/4)
= (√3/4) - (77/4)
= (√3 -77)/4 cm²
Hope This Helps :)
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https://www.meritnation.com/ask-answer/question/3-circles-each-of-radius-3-5-cm-are-drawn-in-such-a-way-that...
This will help you buddy!
This will help you buddy!
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