Three circles each of radius 3.5cm are drawn in such a way that each of them touches the other two. Find the area enclosed between these three circles. Pls answer this
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hey buddy,
here is your ans..
firstly,
find tha side of a triangle formed
ie 3.5+3.5=7.0cm
now,
area of equilateral triangle = root 3/2 (side)^2 = root3/2 (7)^2 = root3*49/2
find the area of 3 sectors formed = theta/360*pi*r^2 =
theta = 60° ( all angles are of 60° in equilateral triangle)
after all the calculation
final step,
area of enclosed part = area of triangle - area of 3 sectors.
I think the calculation you have to do with yourself
I hope it will help you
Thank you..:-) :-)
here is your ans..
firstly,
find tha side of a triangle formed
ie 3.5+3.5=7.0cm
now,
area of equilateral triangle = root 3/2 (side)^2 = root3/2 (7)^2 = root3*49/2
find the area of 3 sectors formed = theta/360*pi*r^2 =
theta = 60° ( all angles are of 60° in equilateral triangle)
after all the calculation
final step,
area of enclosed part = area of triangle - area of 3 sectors.
I think the calculation you have to do with yourself
I hope it will help you
Thank you..:-) :-)
Attachments:
darkknight07:
pleasure :-)
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