Three circles each of radius 7 cm are drawn in such a way that each of their touches the other two.Find the area enclosed between the circles.
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Answer:
THE CIRCLES TOUCHES 2 CIRCLES AND THERE RADIUS OF 7 CM
means rhe inclosed area is of equilaterol triangle whose sides are of 7 cm
therefore ,
area of enclosed part =1/2 X baseX height
=1/2 X 7 X 7
=1/2 X 49
=24.5
- THEREFORE THE AREA ENCLOSED BETWEEN THE CIRCLES BE 24.5 sq.cm
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