Three circles with fixed centres placed one beside the other have diameters 20% more than that of it’s “left neighbour”. If the leftmost circle completes 200 revolutions, how many revolutions will the rightmost circle complete?
Answers
Given : Three circles with fixed centres placed one beside the other have diameters 20% more than that of it’s “left neighbour”. If the leftmost circle completes 200 revolutions,
To find : how many revolutions will the rightmost circle complete?
Solution:
Let say Diameter of left most = D unit
Then Diameter of next = D + (20/100)D = 1.2D unit
Diameter of right most = 1.2D + (20/100)(1/2D) = 1.44 D unit
Circumference = π * Diameter
Circumference of Left most = πD unit
Circumference of next = π(1.2D) unit
Circumference of right most = π(1.44)D unit
1 revolution = Circumference
200 revolution of left most circle = 200 * (πD) unit
Distance covered = 200 * (πD) unit
Distance covered by right most = Revolutions * π(1.44)D
Revolutions * π(1.44)D = 200 * (πD)
=> Revolutions by right most = 200/1.44
=> Revolutions by right most = 138.9
approx 139 revolutions
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