Three coins are tossed, and at least two of them shows tails. what is the probability that other coin shows heads
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1
sample space =(h, h, h), (h, h, t), (h, t, h), (t, h, h), (t, t, t), (t, t, h), (t, h, t), (h, t, t)
a=atleast two of them shows tails
P(a)=4/8 I. e. 1/2
b=coin shows head
P(b)=4/8=1/2
a=atleast two of them shows tails
P(a)=4/8 I. e. 1/2
b=coin shows head
P(b)=4/8=1/2
Answered by
0
Answer:
Step-by-step explanation:Lets analyze the options :
p) If Humpy sits on the wall then he will fall.
This means that by sitting on the wall Humpy falls. This reasonable.
q) If Humpy falls then he was sitting on the wall.
Humpy could fall as a result of any other reason apart from sitting on the wall so this statement is wrong.
r) If Humpy does not fall then he was not sitting on the wall
We cannot rule out this given that we are not so sure that he was supposed to fall when he sits on the wall.
s) If Humpy does not sit on the wall, the he does not fall.
He could still sit on something else and still fall so this statement is not correct.
The correct option is thus p.
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