Question

Three coins are tossed. Find the
probability of all heads:
(A) 118
(B) 3/8
(C) 5/8
(D) 7/8
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Answer 1

Hi friend here is your answer.

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No. of experiments=3

let p be the probability of heads =1/2

And q be the probability of tails = 1/2

then 3C3×p^3×q^0=1×1/8×1=1/8 ans.

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Answer 2

for a single coin probability to come head is

$1 \div 2$

For total 3 coin

$1 \div 2 \times 1 \div 2 \times 1 \div 2 = 1 \div 8$

Your answer is 1÷8