Question

Three coins are tossed once. Find the probability of getting no head.

Answer 1

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Let S be sample space
n(S) - No. of Total outcomes when 3 coins are tossed
$n(S) = 2^{3} = 8$

{°•° No. of Total outcomes when n coins are tossed = $2^{3}$ }

Let E be the Event that No Head shows up when 3 coins are tossed
n(E) - No. of favourable Outcomes for occurrence of Event E

Possible case => All coins show Tails.
E = { T, T, T }
•°• n(E) = 1

Probability of Occurrence of Event E

$P(E) = \frac{No.\: of\: Favourable\: Outcomes}{No.\: of\: Total\: Outcomes}$

$P(E) = \frac{n(E)}{n(S)}$

•°• $\underline{\underline{ Required\: Probability = \frac{1}{8}}}$

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Answer 2

Answer:

Probability for getting no head P(E) =1/8

Step-by-step explanation:

As we know that :

probability of happening an event = $\frac{favourable\:\:outcome}{total\:\:possible\:\:outcome}$

Total Possible outcome of tossing three coins once = 2³ = 8

These are

1. TTT ------->(Favourable outcome)
2. TTH
3. THT
4. THH
5. HTT
6. HTH
7. HHT
8. HHH

Favourable outcomes: for getting no head=1

Probability for getting no head P(E) =1/8