Question

Three coins are tossed simultaneously 200 times

Find the probability of getting at most one head

Answer 1

Given that total number of times coin is tossed = 200.

Let A be the probability of getting atmost 1 head.

⇒ n(A) = No heads + 1 head

           = 28 + 77

           = 105.

Therefore, required probability P(A) = n(A)/n(S) = 105/200.

Hope this helps!

Answer 2

if nö head then 72 + 100

if 77 head then 23 + 100

if 23 head then 77 + 100

then 172 heads